php用户cookie登录验证与mysql数据登录验证的方法:
<?php
unset($username);
if ($_COOKIE['login']) {
list($c_username,$cookie_hash) = split(',',$_COOKIE['login']);
if (md5($c_username.$secret_word) == $cookie_hash) {
$username = $c_username;
} else {
print "You have sent a bad cookie.";
}
}
if ($username) {
print "Welcome, $username.";
} else {
print "Welcome, anonymous user.";
}
?>
看个完整的与数据库连接登录的代码:
<html>
<head>
<title>Log-In Page</title>
</head>
<body>
Please enter your user details to log-in here...
<form action = "authenticate.php" method = "post">
Username:<br>
<input type = "text" name = "username">
<br><br>
Password:<br>
<input type = "text" name = "password">
<br><br>
<input type = "submit" value = "Log In">
</form>
</body>
</html>
File:authenticate.php
<?php
$username = $_POST['username'];
$password = $_POST['password'];
$self = $_SERVER['PHP_SELF'];
$referer = $_SERVER['HTTP_REFERER'];
if( ( !$username ) or ( !$password ) )
{ header( "Location:$referer" ); exit(); }
$conn=@mysql_connect( "localhost", "userName", "password" ) or die( "Could not connect" );
$rs = @mysql_select_db( "my_database", $conn ) or die( "Could not select database" );
$sql = "select * from users where user_name="$username" and password = password( "$password" )";
$rs = mysql_query( $sql, $conn ) or die( "Could not execute query" );
$num = mysql_numrows( $rs );
if( $num != 0 )
{
$msg = "<h3>Welcome $username - your log-in succeeded!</h3>";
}
else
{
header( "Location:$referer" ); exit();
}
?>
<html>
<head>
<title>Log-In Authenticated</title>
</head>
<body>
<?php echo( $msg ); ?>
</body>
</html>
由 dawei
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